Difference between revisions of "Switchback"

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A '''switchback''' is a situation in which a [[ladder]] moves back two rows and changes direction. The attacker is still in control after the switchback. Although it is not always ladder escape, it often can be and is usually a strong play.
+
A '''switchback''' is a situation in which a [[ladder]] moves back two or more rows and changes direction. The attacker is still in control after the switchback. Although it is not always a ladder escape, it often can be and is usually a strong play.
  
The situation prior two a switchback looks like this (assume the piece on D3 is in some way connected to the top):
+
For example, consider the following situation. Assume the piece marked "↑" is connected to the top.
  
<hex>R4 C8 Q1 Vd1, Vc2, Vh1, Hb2, Hd2, Hb4</hex>
+
<hexboard size="4x8"
 +
  coords="none"
 +
  edges="bottom"
 +
  contents="R arrow(12):d1 B d2 R h1 B b2 R c2 B b4"
 +
  />
  
 
Red makes a switchback as follows:
 
Red makes a switchback as follows:
  
<hex>R4 C8 Q1 Vd1, Vc2, Vh1, Hb2, Hd2, Hb4 N:on Vc3, Hc4, Vd3, Hd4, Ve3, He4, Vg3, Hf3</hex>
+
<hexboard size="4x8"
 +
  coords="none"
 +
  edges="bottom"
 +
  contents="R arrow(12):d1 B d2 R h1 B b2 R c2 B b4 R 1:c3 B 2:c4 R 3:d3 B 4:d4 R 5:e3 B 6:e4 R 7:g3 B 8:f3"
 +
  />
  
Now the ladder continues back to the left:
+
Now the ladder continues from right to the left on the 4th row:
  
<hex>R4 C8 Q1 Vd1, Vc2, Vh1, Hb2, Hd2, Hb4, Vc3, Hc4, Vd3, Hd4, Ve3, He4, Vg3, Hf3 Vg3 N:on Vg1, Hf2, Vf1, He2, Ve1</hex>
+
<hexboard size="4x8"
 +
  coords="none"
 +
  edges="bottom"
 +
  contents="R arrow(12):d1 B d2 R h1 B b2 R c2 B b4 R c3 B c4 R d3 B d4 R e3 B e4 R g3 B f3 R 9:g1 B 10:f2 R 11:f1 B 12:e2 R 13:e1"
 +
  />
  
Note here how red was able to connect back to the D3 piece. This is not always possible, but even if it isn't the switchback can be used to create a long line connected to the edge and four rows back from it, a distinct advantage.
+
Note here how Red was able to connect back to the piece marked "↑". This is not always possible, but even if it isn't, the switchback can be used to create a long line connected to the edge and several rows back from it, a distinct advantage.
 +
 
 +
== Specific switchbacks ==
 +
 
 +
=== A3 switchback ===
 +
 
 +
A single piece at a3 (or at the equivalent cell on the opposite site of the board) escapes 2nd row ladders. It can also be used as a 3rd-to-5th row switchback:
 +
 
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h3 R 1:b3 B 2:b4 R 3:c3 B 4:c4 R 5:d3 B 6:d4 R 7:g2 B 8:e3 R 9:f1"
 +
  />
 +
 
 +
Note that at no point in the 3rd row ladder, Blue could have [[yielding|yielded]], because Red's piece could have escaped the resulting 2nd row ladder outright.
 +
 
 +
For an example, see also [[A3 escape trick]].
 +
 
 +
Additionally, even if some of the corner is occupied by the opponent, a single piece at a3 can still be used as a 2nd-to-4th row switchback (but it does not escape 2nd row ladders in this case, nor serve as a 3rd-to-5th row switchback):
 +
 
 +
<hexboard size="4x6"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R f2 B f4 B f3 R 1:b3 B 2:b4 R 3:c3 B 4:c4 R 5:e3 B 6:d3 R 7:e1"
 +
  />
 +
 
 +
=== A4 switchback ===
 +
 
 +
We have already seen in the first example above that a single Red piece at a4 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback. It also works as a 3rd-to-5th row switchback, as follows:
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h2 B b4 R 1:c3 B 2:c4 R 3:d3 B 4:d4 R 5:e3 B 6:e4 R 7:g3 B 8:f3 R 9:g1"
 +
  />
 +
Red's 7 is connected to the bottom, and 9 is the ladder stone in the opposite direction.
 +
 
 +
Note that if Blue had instead decided to yield the ladder to the second row at any point, the outcome for Blue would have been worse: in that case, Red can perform a 2nd-to-4th row switchback which reconnects to Red's 3rd row ladder.
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h2 B b4 R 1:c3 B 2:c4 R 3:d3 B 4:d5 R 5:e4 B 6:e5 R 7:g4 B 8:f4 R 9:g2 B 10:f3 R 11:f2"
 +
  />
 +
 
 +
In addition, a4 can be used as a 4th-to-6th row switchback in the presence of a [[Foldback#Foldback_threat|foldback threat]]:
 +
<hexboard size="6x9"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R i3 B b4 c4 R a6 R 1:d3 B 2:d4 R 3:e3 B 4:e4 R 5:h2 B 6:g3 R 7:f4 B 8:f3 R 9:g1"
 +
  />
 +
Of course, Blue cannot yield, or else Red gets the 3rd-to-5th row switchback and connects.
 +
 
 +
=== C4 switchback ===
 +
 
 +
C4 acts as a [[ladder escape]] for 2nd and 3rd row ladders, as well as for 4th row ladders given either enough space on the 5th row or a [[Foldback#Foldback_threat|foldback threat]]. But in cases where there isn't enough space to do either of the above, c4 may still give a (very short) 4th-to-6th row switchback, like this:
 +
 
 +
<hexboard size="7x9"
 +
  coords="show"
 +
  edges="bottom right"
 +
  contents="R g4 c2 c3 d3 B b4 c5 e3 R 1:d4 B 2:d5 R 3:e4 B 4:e5 R 5:h3 B 6:f4 R 7:g2"
 +
  />
 +
Note that Red is connected to the edge by [[Fifth_row_edge_templates#V-2-a|template V2a]].
 +
 
 +
=== A5 switchback ===
 +
 
 +
A single Red piece at a5 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback and as a 3rd-to-5th row switchback. The 2nd-to-4th row switchback works as follows:
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h1 B a5 R 1:b4 B 2:b5 R 3:c4 B 4:c5 R 5:d4 B 6:d5 R 7:f4 B 8:e4 R 9:f2 E *:h2 E *:f3"
 +
  />
 +
Note that Red's piece 9 is connected to the bottom edge by [[double threat]] at the two cells marked "*". Play then continues leftward along the 4th row.
 +
 
 +
The 3rd-to-5th row switchback works as follows:
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h1 B b4 R 1:c3 B 2:c4 R 3:d3 B 4:d4 R 5:e3 B 6:e4 R 7:g3 B 8:f3 R 9:g1"
 +
  />
 +
 
 +
Once again, yielding would not have helped Blue.
 +
 
 +
In addition, in the presence of a [[Foldback#Foldback_threat|foldback threat]], a5 can also be used as a 4th-to-6th row switchback as follows:
 +
<hexboard size="6x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h2 a6 B b4 R 1:c3 B 2:c4 R 3:d3 B 4:d4 R 5:e3 B 6:e4 R 7:f4 B 8:f3 R 9:g1"
 +
  />
 +
Note that Red is connected to the edge by a [[ladder creation template]]. If Blue tries to yield at any point, Red connects outright by the above 3rd-to-5th row switchback.
 +
 
 +
Moreover, if there is a [[Foldback#Foldback_threat|foldback threat]] that would escape a 3rd row ladder in the opposite direction, a5 can also be used as a 5th-to-7th row switchback as follows:
 +
<hexboard size="7x10"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R c3 B b4 R j3 b6 B c4 R 1:d3 B 2:d4 R 3:e3 B 4:e4 R 5:f3 B 6:f4 R 7:i2 B 8:h3 R 9:g4 B 10:g3 R 11:h1"
 +
  />
 +
For this to work, is is not sufficient if Red can only escape a 2nd row ladder in the opposite direction.
 +
 
 +
=== B5 switchback ===
 +
 
 +
A single Red piece at b5 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback and as a 3rd-to-5th row switchback for the same reasons as [[#A5 switchback|a5]]. Alternatively, with b5, the 2nd-to-4th row switchback can also be played like this:
 +
<hexboard size="6x6"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R e2 a5 B a6 R 1:b5 B 2:b6 R 3:d5 B 4:c5 R 5:d3 E *:d2"
 +
  />
 +
Note that this doesn't require * to be empty, and 5 is connected to the bottom edge by [[Fifth_row_edge_templates#V-2-k|edge template V-2k]].
 +
 
 +
In addition, b5 can be used as a 4th-to-6th row switchback as follows:
 +
<hexboard size="6x6"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R e2 S f1 R a3 B a4 R 1:b3 B 2:b4 R 3:d3 B 4:c3 R 5:d1 E a:c5 b:b5"
 +
  />
 +
Note that Red's 3 is connected by [[Fifth_row_edge_templates#V-2-a|edge template V-2a]]. The shaded cell is not needed for the switchback. If Blue tries to yield to a 3rd row ladder at any point, Red can play the 3rd-to-5th row switchback and connect. Also, playing "a" prior to move 2 does not help Blue since Red can just respond at "b".
 +
 
 +
=== A6 switchback ===
 +
 
 +
A single Red piece at a6 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback as follows:
 +
<hexboard size="6x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h1 R a5 B a6 R 1:b5 B 2:b6 R 3:f4 B 4:c5 R 5:d3 B 6:e4 R 7:d5 B 8:d4 R 9:f2
 +
            B 10:f3 R 11:h2  S area(a1,a2,d2,f1)"
 +
  />
 +
The red stone marked "3" is the unique winning move for Red; in particular, Red cannot push the ladder past "1". After this, Blue has several possible responses, of which only one is shown above. However, Red can complete the switchback (or connect) in all cases. The shaded area is not needed for the switchback.
 +
 
 +
With the amount of space shown here, a6 is not sufficient to switch back a 3rd row ladder. However, with some additional space, this can be done; see [[#B6 switchback|B6 switchback]] and [[#C6 switchback|C6 switchback]] below.
 +
 
 +
A piece at a6 can also help a 2nd-and-4th row [[parallel ladder]] connect in situations where there is just not enough room for [[Tom's move]], for example like this:
 +
<hexboard size="6x6"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R f1 b3 a4 a5 1:d4 3:e4 5:d2 B b4 a6 2:c5 4:c4"
 +
  />
 +
Note that 5 is connected to the red edge by the [[Interior_template#The_shopping_cart|shopping cart]] template and a [[ziggurat]]. If Blue had played anywhere other than 2 and 4 (possibly after [[intrusion|intruding]] into the ziggurat, which Red defends), Red would have connected even without a6.
 +
 
 +
=== B6 switchback ===
 +
 
 +
A single Red piece at b6 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback for the same reason as [[#A6 switchback|a6]], using this much space:
 +
<hexboard size="6x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R g1 R a5 B a6 R 1:b5 B 2:b6 R 3:f4 B 4:c5 R 5:d3 B 6:e4 R 7:d5 B 8:d4 R 9:f2
 +
            B 10:f3 R 11:h2 S area(a1,a2,d2,f1)"
 +
  />
 +
It can also be used as a 3rd-to-6th row switchback. It Blue does not yield, the 3rd-to-6th row switchback works as follows:
 +
<hexboard size="6x6"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R e1 R a4 B a5 R 1:b4 B 2:b5 R 3:c4 B 4:c5 R 5:e4 B 6:d4 R 7:f2"
 +
  />
 +
If Blue yields, the situation is more complicated (depending on the exact moment when Blue yields), but Red still gets the switchback.
 +
 
 +
=== C6 switchback ===
 +
 
 +
A single Red piece at c6 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback for the same reason as [[#A6 switchback|a6]] and as a 3rd-to-6th row switchback for the same reason as [[#B6 switchback|b6]]; moreover, it can also be used as a 3rd-to-5th row switchback. If Blue does not yield, the 3rd-to-5th row switchback can be played as follows:
 +
<hexboard size="6x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R f1 R a4 B a5 R 1:b4 B 2:b5 R 3:d4 B 4:c4 R 5:d2 B 6:d3 R 7:f2
 +
            S g1 h1 h2 h3"
 +
  />
 +
Note that Red is connected to the edge by [[Fifth_row_edge_templates#V-2-f|edge template V-2f]]. The shaded hexes are not needed for the switchback to work. There are other possible responses by Blue that are not shown here, but in any case Red can get at least the switchback. 
 +
 
 +
If Blue tries to yield to the 2nd row, Red still gets the switchback, and can sometimes connect outright. If Blue yields early enough, Red has enough room to play the 2nd-to-4th row switchback (see [[#A6 switchback|A6 switchback]] above) and connect. If Blue yields closer to the switchback stone, Red's play is less obvious and depends on the exact moment when Blue yields.
 +
<!--
 +
<hexboard size="6x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R f1 R 1:a4 B 2:a6 R 3:b5 B 4:b6 R 5:e4
 +
            S g1 h1 h2 h3"
 +
  />
 +
-->
 +
 
 +
=== B3-without-C1 switchback ===
 +
 
 +
A single Red stone at b3 (or the equivalent cell on the opposite side of the board) escapes 2nd row ladders. It can also be used as a 3rd-to-5th row switchback. This works very similarly to the [[#A3 switchback|a3 switchback]].
 +
 
 +
<hexboard size="5x9"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h3 B g5 R 1:b3 B 2:b4 R 3:c3 B 4:c4 R 5:d3 B 6:d4 R 7:g2 B 8:e3 R 9:f1"
 +
  />
 +
 
 +
=== C5-without-C1 switchback ===
 +
 
 +
A single Red piece at c5 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback and, with enough space, as a 3rd-to-5th row switchback, even if the opponent occupies c1.
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R f1 B f5"
 +
  />
 +
 
 +
The 2nd-to-4th row switchback is analogous to the [[#A5 switchback|A5 switchback]] and can be played as follows:
 +
<hexboard size="5x8"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R f1 B f5 R a4 B a5 R b4 B b5 R 1:c4 B 2:c5 R 3:e4 B 4:d4 R 5:e2 B 6:e3 R 7:g2
 +
            S h1 h2"
 +
  />
 +
Note that 7 is connected to the edge by [[edge template IV2e]]. The shaded cells are not required for the switchback.
 +
 
 +
The 3rd-to-5th row switchback is harder to pull off and requires some space on the 6th row. It can be played as follows:
 +
<hexboard size="6x9"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R g2 B g6 R a4 B a5 R 1:b4 B 2:b5 R 3:f3
 +
            S a1 b1 c1 d1 h1 i1 i2 i3"
 +
  />
 +
Within the area shown, 3 is the unique winning move (i.e., the unique move that permits Red to complete the switchback). Note that 3 is already connected to the edge by [[Fifth_row_edge_templates#V-2-d|edge template V-2d]]. The shaded cells are not required for the switchback. After move 3, there are a number of possibilities depending on Blue's response. A typical sequence is the following:
 +
<hexboard size="6x9"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R g2 B g6 R a4 B a5 R 1:b4 B 2:b5 R 3:f3 B 4:c4 R 5:d2 B 6:e2 R 7:d3 B 8:e4 R 9:f5 B 10:d4 R 11:e3 B 12:f4 R 13:h3
 +
            S a1 b1 c1 d1 h1 i1 i2 i3"
 +
  />
 +
At this point, Red is connected to the edge by [[edge template IV2e]]. If Blue instead decides to yield the 3rd row ladder to the 2nd row, Red has enough room to play the 2nd-to-4th row switchback and connect.
 +
 
 +
The C5-without-C1 situation can also ''almost'' be used for a 4th-to-6th row switchback. While Blue can defend against this, the defense is not obvious and there is very little room for error. Therefore, this is a useful situation for the defender to be aware of. Consider the following position, with Blue to move:
 +
<hexboard size="6x10"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h2 B h6 R a3 B a4 R 1:b3 B 2:b4 R 3:c3 E a:c4 b:d5 c:b6"
 +
  />
 +
Note that if Blue had tried to yield at any time prior to move 3, Red could have used the 3rd-to-5th row switchback to connect. After move 3, Blue has only three options, marked "a", "b", and "c". Option "a" is pushing the ladder. Options "b" and "c" prevent Red from getting the switchback, but Red will get a [[foldback|foldback underneath]] instead, i.e., a 2nd row ladder going right-to-left (this also serves as a ladder escape fork for any Red 2nd row ladders arriving from the left). So "a" is Blue's best option.
 +
<hexboard size="6x10"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="R h2 B h6 R a3 B a4 R 1:b3 B 2:b4 R 3:c3 B 4:c4 R 5:d3 E x:e3 y:g3 a:d5 b:e5"
 +
  />
 +
At this point, if Blue continues to push the ladder, Red will play at "x" and then at "y" to form [[Fifth_row_edge_templates#V-2-d|edge template V-2d]] and get the switchback. The only possible moves for Blue to prevent the switchback are "a" and "b". If Blue moves at "b", then Red gets a foldback underneath. Therefore, Blue's best option is "a". Now Red gets neither the switchback nor a foldback underneath. Red still gets a [[ladder escape fork]] for 2nd row ladders arriving from the left.
 +
 
 +
=== 2nd-to-6th row switchback ===
 +
 
 +
Perhaps surprisingly, giving enough space, it is possible for the attacker in a 2nd row ladder to force a switchback to a [[Theory_of_ladder_escapes#Second_and_fourth_row_terraced_ladders|terraced ladder]] on the 4th and 6th rows, ''without the help of any additional pieces''. Red can initiate this maneuver by playing the piece marked 5 in the following diagram. The shaded cells are not required for this trick (i.e., they may be occupied by Blue).
 +
<hexboard size="6x11"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="S i1 j1 j2 k1 k2 k3 R 1:a5 B 2:a6 R 3:b5 B 4:b6 R 5:g3"
 +
  />
 +
This position is complicated to analyze, with many possible lines of play, but it can be shown that the following sequence is [[optimal play|optimal]] for both Red and Blue. In other words, Blue cannot prevent Red from getting the switchback, and Red cannot do better (within the amount of space shown here) than getting a terraced ladder on the 4th and 6th row.
 +
<hexboard size="6x11"
 +
  coords="hide"
 +
  edges="bottom right"
 +
  contents="S i1 j1 j2 k1 k2 k3 R 1:a5 B 2:a6 R 3:b5 B 4:b6 R 5:g3 B 6:d5 R 7:e3 B 8:d4 R 9:d3 B 10:f4 R 11:e5 B 12:e4 R 13:h2 B 14:f3 R 15:g1 B 16:f2 R 17:f1"
 +
  />
 +
Also note that, while the resulting right-to-left terraced ladder is on the 4th and 6th rows, it is effectively a 2nd-and-4th row terraced ladder since Red already has a solid edge of pieces on the 2nd row.
 +
 
 +
== Switchback threat ==
 +
 
 +
We say that a ladder carries a ''switchback threat'' if getting a switchback would allow the attacker to connect. Even if the attacker cannot actually carry out a switchback, the existence of a switchback threat can sometimes give the attacker an advantage. For example, consider the following situation, with Red to move:
 +
<hexboard size="7x7"
 +
  coords="hide"
 +
  edges="all"
 +
  contents="R a5 a6 b3 b4 b6 e2 B a7 b5 b7 d3 e3 f6 E *:c4 R 1:c6 B 2:c7"
 +
  />
 +
Note that the 2nd row ladder carries a switchback threat, because any potential switchback would connect at "*". This allows Red to play as follows and win:
 +
<hexboard size="7x7"
 +
  coords="hide"
 +
  edges="all"
 +
  contents="R a5 a6 b3 b4 b6 e2 B a7 b5 b7 d3 e3 f6 E *:c4 R c6 B c7 R 3:e6 B 4:d6 R 5:f4 B 6:e4 R 7:g2"
 +
  />
 +
Note that after move 5, Blue had no choice but to defend at 6, or else Red would have gotten the switchback. On the other hand, without the switchback threat, for example if Blue had a stone at "*", this position would be losing for Red.
 +
 
 +
For more examples of how switchback threats can be useful, see also [[Climbing#Climbing_from_a_ladder|climbing from a ladder]].
 +
 
 +
[[Category: Definition]]
 +
[[Category: Ladder]]
 +
[[Category: Intermediate Strategy]]

Latest revision as of 22:47, 18 March 2024

A switchback is a situation in which a ladder moves back two or more rows and changes direction. The attacker is still in control after the switchback. Although it is not always a ladder escape, it often can be and is usually a strong play.

For example, consider the following situation. Assume the piece marked "↑" is connected to the top.

Red makes a switchback as follows:

13587246

Now the ladder continues from right to the left on the 4th row:

131191210

Note here how Red was able to connect back to the piece marked "↑". This is not always possible, but even if it isn't, the switchback can be used to create a long line connected to the edge and several rows back from it, a distinct advantage.

Specific switchbacks

A3 switchback

A single piece at a3 (or at the equivalent cell on the opposite site of the board) escapes 2nd row ladders. It can also be used as a 3rd-to-5th row switchback:

971358246

Note that at no point in the 3rd row ladder, Blue could have yielded, because Red's piece could have escaped the resulting 2nd row ladder outright.

For an example, see also A3 escape trick.

Additionally, even if some of the corner is occupied by the opponent, a single piece at a3 can still be used as a 2nd-to-4th row switchback (but it does not escape 2nd row ladders in this case, nor serve as a 3rd-to-5th row switchback):

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A4 switchback

We have already seen in the first example above that a single Red piece at a4 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback. It also works as a 3rd-to-5th row switchback, as follows:

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Red's 7 is connected to the bottom, and 9 is the ladder stone in the opposite direction.

Note that if Blue had instead decided to yield the ladder to the second row at any point, the outcome for Blue would have been worse: in that case, Red can perform a 2nd-to-4th row switchback which reconnects to Red's 3rd row ladder.

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In addition, a4 can be used as a 4th-to-6th row switchback in the presence of a foldback threat:

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Of course, Blue cannot yield, or else Red gets the 3rd-to-5th row switchback and connects.

C4 switchback

C4 acts as a ladder escape for 2nd and 3rd row ladders, as well as for 4th row ladders given either enough space on the 5th row or a foldback threat. But in cases where there isn't enough space to do either of the above, c4 may still give a (very short) 4th-to-6th row switchback, like this:

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Note that Red is connected to the edge by template V2a.

A5 switchback

A single Red piece at a5 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback and as a 3rd-to-5th row switchback. The 2nd-to-4th row switchback works as follows:

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Note that Red's piece 9 is connected to the bottom edge by double threat at the two cells marked "*". Play then continues leftward along the 4th row.

The 3rd-to-5th row switchback works as follows:

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Once again, yielding would not have helped Blue.

In addition, in the presence of a foldback threat, a5 can also be used as a 4th-to-6th row switchback as follows:

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Note that Red is connected to the edge by a ladder creation template. If Blue tries to yield at any point, Red connects outright by the above 3rd-to-5th row switchback.

Moreover, if there is a foldback threat that would escape a 3rd row ladder in the opposite direction, a5 can also be used as a 5th-to-7th row switchback as follows:

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For this to work, is is not sufficient if Red can only escape a 2nd row ladder in the opposite direction.

B5 switchback

A single Red piece at b5 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback and as a 3rd-to-5th row switchback for the same reasons as a5. Alternatively, with b5, the 2nd-to-4th row switchback can also be played like this:

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Note that this doesn't require * to be empty, and 5 is connected to the bottom edge by edge template V-2k.

In addition, b5 can be used as a 4th-to-6th row switchback as follows:

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Note that Red's 3 is connected by edge template V-2a. The shaded cell is not needed for the switchback. If Blue tries to yield to a 3rd row ladder at any point, Red can play the 3rd-to-5th row switchback and connect. Also, playing "a" prior to move 2 does not help Blue since Red can just respond at "b".

A6 switchback

A single Red piece at a6 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback as follows:

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The red stone marked "3" is the unique winning move for Red; in particular, Red cannot push the ladder past "1". After this, Blue has several possible responses, of which only one is shown above. However, Red can complete the switchback (or connect) in all cases. The shaded area is not needed for the switchback.

With the amount of space shown here, a6 is not sufficient to switch back a 3rd row ladder. However, with some additional space, this can be done; see B6 switchback and C6 switchback below.

A piece at a6 can also help a 2nd-and-4th row parallel ladder connect in situations where there is just not enough room for Tom's move, for example like this:

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Note that 5 is connected to the red edge by the shopping cart template and a ziggurat. If Blue had played anywhere other than 2 and 4 (possibly after intruding into the ziggurat, which Red defends), Red would have connected even without a6.

B6 switchback

A single Red piece at b6 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback for the same reason as a6, using this much space:

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It can also be used as a 3rd-to-6th row switchback. It Blue does not yield, the 3rd-to-6th row switchback works as follows:

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If Blue yields, the situation is more complicated (depending on the exact moment when Blue yields), but Red still gets the switchback.

C6 switchback

A single Red piece at c6 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback for the same reason as a6 and as a 3rd-to-6th row switchback for the same reason as b6; moreover, it can also be used as a 3rd-to-5th row switchback. If Blue does not yield, the 3rd-to-5th row switchback can be played as follows:

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Note that Red is connected to the edge by edge template V-2f. The shaded hexes are not needed for the switchback to work. There are other possible responses by Blue that are not shown here, but in any case Red can get at least the switchback.

If Blue tries to yield to the 2nd row, Red still gets the switchback, and can sometimes connect outright. If Blue yields early enough, Red has enough room to play the 2nd-to-4th row switchback (see A6 switchback above) and connect. If Blue yields closer to the switchback stone, Red's play is less obvious and depends on the exact moment when Blue yields.

B3-without-C1 switchback

A single Red stone at b3 (or the equivalent cell on the opposite side of the board) escapes 2nd row ladders. It can also be used as a 3rd-to-5th row switchback. This works very similarly to the a3 switchback.

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C5-without-C1 switchback

A single Red piece at c5 (or the equivalent cell on the opposite side of the board) can be used as a 2nd-to-4th row switchback and, with enough space, as a 3rd-to-5th row switchback, even if the opponent occupies c1.

The 2nd-to-4th row switchback is analogous to the A5 switchback and can be played as follows:

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Note that 7 is connected to the edge by edge template IV2e. The shaded cells are not required for the switchback.

The 3rd-to-5th row switchback is harder to pull off and requires some space on the 6th row. It can be played as follows:

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Within the area shown, 3 is the unique winning move (i.e., the unique move that permits Red to complete the switchback). Note that 3 is already connected to the edge by edge template V-2d. The shaded cells are not required for the switchback. After move 3, there are a number of possibilities depending on Blue's response. A typical sequence is the following:

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At this point, Red is connected to the edge by edge template IV2e. If Blue instead decides to yield the 3rd row ladder to the 2nd row, Red has enough room to play the 2nd-to-4th row switchback and connect.

The C5-without-C1 situation can also almost be used for a 4th-to-6th row switchback. While Blue can defend against this, the defense is not obvious and there is very little room for error. Therefore, this is a useful situation for the defender to be aware of. Consider the following position, with Blue to move:

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Note that if Blue had tried to yield at any time prior to move 3, Red could have used the 3rd-to-5th row switchback to connect. After move 3, Blue has only three options, marked "a", "b", and "c". Option "a" is pushing the ladder. Options "b" and "c" prevent Red from getting the switchback, but Red will get a foldback underneath instead, i.e., a 2nd row ladder going right-to-left (this also serves as a ladder escape fork for any Red 2nd row ladders arriving from the left). So "a" is Blue's best option.

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At this point, if Blue continues to push the ladder, Red will play at "x" and then at "y" to form edge template V-2d and get the switchback. The only possible moves for Blue to prevent the switchback are "a" and "b". If Blue moves at "b", then Red gets a foldback underneath. Therefore, Blue's best option is "a". Now Red gets neither the switchback nor a foldback underneath. Red still gets a ladder escape fork for 2nd row ladders arriving from the left.

2nd-to-6th row switchback

Perhaps surprisingly, giving enough space, it is possible for the attacker in a 2nd row ladder to force a switchback to a terraced ladder on the 4th and 6th rows, without the help of any additional pieces. Red can initiate this maneuver by playing the piece marked 5 in the following diagram. The shaded cells are not required for this trick (i.e., they may be occupied by Blue).

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This position is complicated to analyze, with many possible lines of play, but it can be shown that the following sequence is optimal for both Red and Blue. In other words, Blue cannot prevent Red from getting the switchback, and Red cannot do better (within the amount of space shown here) than getting a terraced ladder on the 4th and 6th row.

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Also note that, while the resulting right-to-left terraced ladder is on the 4th and 6th rows, it is effectively a 2nd-and-4th row terraced ladder since Red already has a solid edge of pieces on the 2nd row.

Switchback threat

We say that a ladder carries a switchback threat if getting a switchback would allow the attacker to connect. Even if the attacker cannot actually carry out a switchback, the existence of a switchback threat can sometimes give the attacker an advantage. For example, consider the following situation, with Red to move:

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Note that the 2nd row ladder carries a switchback threat, because any potential switchback would connect at "*". This allows Red to play as follows and win:

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Note that after move 5, Blue had no choice but to defend at 6, or else Red would have gotten the switchback. On the other hand, without the switchback threat, for example if Blue had a stone at "*", this position would be losing for Red.

For more examples of how switchback threats can be useful, see also climbing from a ladder.